(3x+2)(x+1)=3x^2+17

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Solution for (3x+2)(x+1)=3x^2+17 equation: 


Simplifying
(3x + 2)(x + 1) = 3x2 + 17

Reorder the terms:
(2 + 3x)(x + 1) = 3x2 + 17

Reorder the terms:
(2 + 3x)(1 + x) = 3x2 + 17

Multiply (2 + 3x) * (1 + x)
(2(1 + x) + 3x * (1 + x)) = 3x2 + 17
((1 * 2 + x * 2) + 3x * (1 + x)) = 3x2 + 17
((2 + 2x) + 3x * (1 + x)) = 3x2 + 17
(2 + 2x + (1 * 3x + x * 3x)) = 3x2 + 17
(2 + 2x + (3x + 3x2)) = 3x2 + 17

Combine like terms: 2x + 3x = 5x
(2 + 5x + 3x2) = 3x2 + 17

Reorder the terms:
2 + 5x + 3x2 = 17 + 3x2

Add '-3x2' to each side of the equation.
2 + 5x + 3x2 + -3x2 = 17 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
2 + 5x + 0 = 17 + 3x2 + -3x2
2 + 5x = 17 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
2 + 5x = 17 + 0
2 + 5x = 17

Solving
2 + 5x = 17

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 5x = 17 + -2

Combine like terms: 2 + -2 = 0
0 + 5x = 17 + -2
5x = 17 + -2

Combine like terms: 17 + -2 = 15
5x = 15

Divide each side by '5'.
x = 3

Simplifying
x = 3

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